A rigid tank contains 50 kg of saturated liquid water at 90d

A rigid tank contains 50 kg of saturated liquid water at 90degreeC. Determine the pressure in the tank and the volume of the tank.

Boiling point and pressure are related to each other by the equation:

Tb = (1/To - R*ln(P/Po)/Hvap)^-1

where

Tb = boiling point = 90 deg C = 90 +273 = 363 K

To = 100 deg C = 100+273 = 373 K

R = gas constant = 8.314

Po = 1 atm

P = pressure required

Hvap = heat of vaporization of water = 40.66 kJ/mol = 4.066*10^4 J/mol

So, 363 = (1/373 - 8.324*ln(P/1)/(4.066*10^4))^-1

So, P = 0.697 atm = 1.013*0.697*10^5 Pa = 7.06*10^4 Pa <-----answer