A sample of n9 scores has a mean of M46 and a variance of s

A sample of n=9 scores has a mean of M=46 and a variance of s^ 2=36. What is the estimated standard error for this sample?

Standard Error= sd/ Sqrt(n)
Where,
sd = Standard Deviation
n = Sample Size

Standard deviation( sd )=6
Sample Size(n)=9
Standard Error = ( 6/ Sqrt ( 9) )
= 2