For each real value of k the equation y kx13defines a famil

For each real value of k, the equation y = kx-1/3defines a family of curves
in the xy-plane. Find an algebraic equation that defines the family of curves
which are orthogonal to the given family.

Solution

k is a constant so we have:

y = kx - 1/3

(y + 1/3) = kx

(y+1/3)/x = k

Now differentiate both sides:

[(y\'+0)*x - 1*(y + 1/3)]/x2 = 0

y\'x - (y+1/3) = 0

So the differentil equation is:

y\' = (y+1/3)/x

So the equation of the orthogonal curve is:

y\' = -1/((y+1/3)/x) = -x/(y + 1/3)

For each real value of k, the equation y = kx-1/3defines a family of curves in the xy-plane. Find an algebraic equation that defines the family of curves which

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