Two accounting professors decided to compare the variance of

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this, they each graded the same 10 exams with the following results:

At the 1% level of significance, what is the decision?

Mean Grade Standard Deviation
Professor 1 79.3 22.4
Professor 2 82.1 12.0

Solution

As

F = s1^2 /s^2 = 22.4^2/12.0^2 = 3.4844

As

df1 = df2 = 10 - 1 = 9, then we see that (from table/technology),

Fcrit = 6.541089627

As F < Fcrit, then we FAIL TO REJECT THE NULL HYPOTHESIS.

We have insufficient evidence to say that there is a difference between the variances of their grading procedures.

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this, they each graded the same 10 exams with the following

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