You are encouraged to work in groups on these problems but y
Solution
Answer:
(1)
Answer: 1/8
Affected brother: XmY
Woman whose brother is affected: XX or XmX (1/2 or 50% chances that she is a carrier)
If a carrier female marries a normal man there is ¼ chances that she could have a child with Duchenne dystrophy.
The above mentioned woman is ½ being a carrier, therefore probability of having a child with Duchenne dystrophy is ½ x ¼ =
(b)
If a carrier female marries a normal man there is ½ child will inherit the disease allele.
My mother being a disease carrier = ½
Me carrying the disease allele= ½ x ½ =1/4
In an X linked recessive inheritance, two copies of a disease allele on the X chromosome are required for an individual with two X chromosomes (a female) to be affected with an X-linked recessive disease.
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
