find the margin of error for the given values of c s and n c

find the margin of error for the given values of c, s and n. c=.95, s=2.3, n=17

Solution

I assume that the notation \"c + .90\" was supposed to be \"c = 0.90\" and is meant to indicate a 90% confidence interval.

If so, the margin of error is:

E = z * s / ?n

For a 90% confidence interval, use z = 1.645.

Substituting the value for z, s, and n gives:

E = (1.645)(3.1) / ?100

E = 0.5100