Solve the following system of equations for x y and z 2 0 0

Solve the following system of equations for x, y, and z: (2 0 0) x + (3 1 0)y + (1 1 3)z = (6 2 3)

Solution

2X+3Y+Z =6

0+Y+Z=2

0+0+3Z =3 are the set of equations represented

=>Z =3/3

=>Z =1

Z=1,Y+Z =2

=>Y+1=2=>Y =1

Y =1, Z =1, 2X +3Y +Z =6

2X +3+1=6

2X =2

X =1

therefore solution is X =1,Y=1,Z=1