An inductor is connected to a 20 kHz oscillator The peak cur

An inductor is connected to a 20 kHz oscillator. The peak current is 67 mA when the rms voltage is 6.8 V. What is the value of the inductance L?

Solution

The impedance Z = V_p / I_p

V_p = sqrt 2 x V_rms

Z = (sqrt 2 x V_rms) / I_p

Z, the impedance, is the inductive reactance, X_L = 2 pi f L

X_L = (sqrt 2 x V_rms) / I_p

L = (sqrt 2 x V_rms) / ( 2 pi f I_p  )

= (sqrt 2 * 6.8 ) / ( 2 * pi * 20 * 10³ x 67 x 10^-3)

L = 0.00114 H = 1.14 mH