In a radio link is required to send digital voice at 4800bps

In a radio link is required to send digital voice at 4800bps,but can only support a symbol rate of 1200 baud, how many symbol states must be used for this implementation?

Solution

Ans)

As we need speed of 4800 bps but radio link supports 1200 baud,

then number of bits represented by each symbol is 4800/1200=4 bits/symbol

then number of symbol states =2^{(number of bits/symbol)}=2⁴=16

so answer is required symbol states =16