At a local soda factory machines are programmed to fill each
Solution
Formulating the null and alternative hypotheses,
Ho: u = 12
Ha: u =/ 12
As we can see, this is a two tailed test.
Thus, getting the critical t,
df = n - 1 = 4
tcrit = +/- 2.776445105
Getting the test statistic, as
X = sample mean = 12.01
uo = hypothesized mean = 12
n = sample size = 5
s = standard deviation = 0.029154759
Thus, t = (X - uo) * sqrt(n) / s = 0.766964989
As |t| < 2.776, we FAIL TO REJECT THE NULL HYPOTHESIS.
Thus, there is no significant deviation of the mean from 12 oz. The machine should not be adjusted. [CONCLUSION]
