A research center surveyed the demand for the video games in

A research center surveyed the demand for the video games in a sample of 50 students, The sum of the demand for the video games is 638, and the sum of the squared differences between each demand and the mean is 519.89. What is the sample standard deviation of the demand for the video games?

Solution

As

s = sqrt(SSE/(n-1))

then

s = sqrt(519.89/(50-1)) = 3.257299495

or

s = 3.3 [ANSWER, A]