Given the graphs of fx solid and gx dotted The domain is 14

Given, the graphs of f(x) (solid) and g(x) (dotted). The domain is [-1,4]. Find the following. f(x) - g(x) > 0 (f + g) (3) (f g) (1)

Solution

We are given graph of f(x) and g(x)

(A)

We have to find intervals where f(x)-g(x) >0

From -1 to 0:

Here , we can see that g(x) >f(x)

so, this can not be interval for f(x)-g(x) >0

From 0 to 2 :

We can see that

f(x)>g(x)

so, this interval is for f(x)-g(x) >0

From 2 to 4 :

Here , we can see that

g(x) > f(x)

so, this can not be interval for f(x)-g(x) >0

(B)

(f+g)(3)

=f(3) +g(3)

f(3)=-1

g(3)=2

(f+g)(3)=-1+2=1

(f+g)(3)=1.........Answer

(C)

(f*g)(1)

=f(1) *g(1)

f(1)=1

g(1)=-2

(f*g)(1)=1*-2

(f*g)=-2.........Answer