Consider an acre of farmland renting for the average price o

Consider an acre of farmland renting for the average price of $150/ acre. Assume that it recieves an average of 250 W/m^2 PAR (photosynthetic active radiation) for 10 hr/ day over a 120 day growing season. If you could capture this at 50% efficiency, what would be the \"land rent-only cost of this energy?

Please show work!!

Solution

First we need to know how hours will be recieves that energy

10 hours --------------- 1 day

x hours ---------------- 120 days

x = 10*120 /1 = 1200 hours

Now we need to know how much enery is produce or recieve in 1200 hours

if 250 W/m^2 ----------------- 10 hours

x ---------------------------------1200 hours

x= 1200*250 / 10 = 30,000 W/m^2

of this enery we only capture 50% so 30,000 * 0.50 = 15,000 W/m^2

Cost of this enery = 150[$/acre]/ 15000[W/m^2]= 0.01 $ / W