923M Listed below are the amounts of mercury in parts per mi

923M Listed below are the amounts of mercury (in parts per million, or ppm) found in tuna sushi sampled at different store The sample mean is 1.024 ppm and the sample standard deviation is 0.240 ppm. Use technology to construct 90% confidence interval estimate of the mean amount of mercury in the population. 0.68 1.32 1.19 0.72 .14 1.11 1.01 What is the confidence interval estimate of the mean amount of mercury in the population? ppm (Round to three decimal places as needed.) X1094 s d: o, 240 l0o

Solution

Note that              
Margin of Error E = t(alpha/2) * s / sqrt(n)              
Lower Bound = X - t(alpha/2) * s / sqrt(n)              
Upper Bound = X + t(alpha/2) * s / sqrt(n)              
              
where              
alpha/2 = (1 - confidence level)/2 =    0.05          
X = sample mean =    1.024          
t(alpha/2) = critical t for the confidence interval =    1.943180281          
s = sample standard deviation =    0.24          
n = sample size =    7          
df = n - 1 =    6          
Thus,              
Margin of Error E =    0.176268747          
Lower bound =    0.847731253          
Upper bound =    1.200268747          
              
Thus, the confidence interval is              
              
(   0.847731253   ,   1.200268747   ) [ANSWER]