A baseball team has 12 pitchers on its roster Three of the p

A baseball team has 12 pitchers on its roster. Three of the pitchers are left-handed. A. One of the pitchers is chosen at random to participate in a charity game. What is the probability that the pitcher is left-handed? B. What is the probability that the pitcher is not left-handed? C. What are the odds in favor of the pitcher being right-handed?

Solution

Here,

p(left) = 3/12 = 0.25
p(right) = 1-P(left) = 0.75

Thusm

a)

P(left) = 0.25

b)

P(not left) = 1 - P(left) = 0.75

c)

odds for right handed = P(right) / P(left) = 0.75/0.25 = 3 [answer]