I need help with question 14 given the information above The

The following information pertains to Questions 13-17 Consider standard W-band rectangular waveguide (WR-10 Use the table belo for dir en sons and other i formation about the guide, and take c = 3x 108 ms and no . 120m ). APPENDIXI STANDARD RECTANGULAR WAVEGUIDE DATA APPENDIXI STANDARD Recommended TEieCu FrequeacyFreqaency Dsignation Dimensions lnches (cm) Dimensioes Inches (om) WR.XX 6660 x 3.410 (16916 x 81.. 0.908 (1631 x 8255) 4.300 x 2.1S0 1.372 10.922 xS,461) (11.328 x 5.867 260-3.93 2840 x 1.340 3.000 x 1300 3.152 WR-187 WR-137 5.259 WR-112 1872 × 0872 (4755 × 2215) 1.372 x 0622 2000 x 1000 CSON 2540 500 x0.750 .122 0497 1.250 x 0425 820-124 a286 x 1,016) 0622 0311 40 x 1270) 0.702 x039 Ka 124-180 WR-62 0420 x 0.170 (1.07 x 043) 0280 x 0.140 (1.27 x 063s) 0360 x 0 220 0224 x 0.112 057 028) 0304 x Q192 0772 x 0488 0268 x 0174 (0681 x 0442 0 228 x 0154 (0.579 x 039) 0.202 x Q.14 (0513 x 0.356 0 180 x 0.130 400600 (048 x 024) 0.1480.074 (038 0.19 0.122 x 0.061 (031 x 0013) 0.100 x 0050 WR-12 WR-10 75.0-1100 900-1400 1100-170.0 140.0-220.0 115.750 x0127) 0.080 x 0.040 0160 x 0.120 0145 x 01125 (0170 × 0083) 308 x 02838) 0051 0.0255 (0.130 x 00648) (0333 2680

Solution

the cut off frequency of rectangular guide is F_c= C/ 2*a

where F_c is cut off frequency

c is light velocity

a is large internal dimension of the wave guide ( In Meters)

In the given table for w band the internal dimension is 0.100X0.050 in centimeters

so cut off frequency is F_c is 3x10⁸/ (2x(0.100x0.050/100)) = 300GHz