In case E a positive point charge with Q is a distance s awa

In case E, a positive point charge with +Q is a distance s away from a second positive point charge +q. In case F ten positive point charges, each with charge +Q/10, lie along an are of radius centered on a positive point charge +q. Is the net electric force on the +q charge in case E greater than, less than, or equal to the net electric force on the +q charge in case F? Explain.

Solution

The force on the charge +q in case E is greater than that in case F. This is because the sine components of the force get cancelled and the force on +q is only due to cos components.