At t 0 a block with mass M 5 kg moves with a velocity v 2
At t = 0 a block with mass M = 5 kg moves with a velocity v = 2 m/s at position xo = -.33 m from the equilibrium position of the spring. The block is attached to a massless spring of SPRING CONSTANT k = 61.2 N/mand slides on a frictionless surface. At what time will the block next pass x = 0, the place where the spring is unstretched?
t1 =
x=0 0Solution
The spring and mass will oscillate with an amplitude determined by the initial amount of energy the spring was given by an external factor.
A = sqrt [x02 + (m/k)v2 ]
= sqrt [0.332 + (5/61.2) * 22 ]
= 0.66 m
x = A * sin (sqrt (k/m) * t1)
t1 = sin( x / A) / sqrt (k / m)
= sin (0.33 / 0.66) / sqrt ( 61.2 / 5 )
t1 = 0.15 s
