At what points on the graph of fx 2x3 3x2 8x is the slope

At what points on the graph of f(x) = 2x^3 - 3x^2 - 8x is the slope of the tangent line 4?

f(x) = 2x³ - 3x² - 8x

f\'(x) = 6x² -6x - 8 = 4

=> 6x² -6x - 12 = 0

This gives x = 2 , -1

The corresponding f(x) (at x = 2) = -12

f(x) (at x =-1) = 3

$At what points on the graph of f(x) = 2x^3 - 3x^2 - 8x is the slope of the tangent line 4?Solutionf(x) = 2x3 - 3x2 - 8x f\'(x) = 6x2 -6x - 8 = 4 => 6x2 -6x -$

At what points on the graph of fx 2x3 3x2 8x is the slope

Solution

Get Help Now

Submit a Take Down Notice