The time it takes a hiker to spot a deer is exponentially di

The time it takes a hiker to spot a deer is exponentially distributed with a mean of 22 minutes. Find the:

(a) probability it will take over 30 minutes for her to spot a deer.

(b) 20th percentile for the time it takes her to spot a deer

(c) standard deviation in the time it takes her to spot the next deer.

Please show the steps on how to do each problem. Thank you!

Solution

Given X follows Exponential distribution with mean =22

F(x)=1-exp(-x/22) for x>0

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(a) probability it will take over 30 minutes for her to spot a deer.

P(X>30)=1-(1-exp(-30/22))=0.2557292

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(b) 20th percentile for the time it takes her to spot a deer

F(x)=1-exp(-x/22) =0.2

--> exp(-x/22) =1-0.2=0.8

--> -x/22 = log(0.8)

So x= -22*log(0.8)=4.909158

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(c) standard deviation in the time it takes her to spot the next deer.

standard deviation =22

The time it takes a hiker to spot a deer is exponentially distributed with a mean of 22 minutes. Find the: (a) probability it will take over 30 minutes for her

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