If angle A is 45 degrees and angle B is 60 degrees Find sinA
If angle A is 45 degrees and angle B is 60 degrees.
Find sin(A)cos(B)
½ (sin(105) + sin(345))
½ (sin(105) - sin(345))
½ (sin(345) + cos(105))
½ (sin(345) - cos(105))
Solution
sin(A)cos(B) =(1/2)[sin(A+B)+sin(A-B)]
=(1/2)[sin(45+60)+sin(45-60)]
=(1/2)[sin(105)+sin(-15)]
=(1/2)[sin(105)+sin(345)]
