If angle A is 45 degrees and angle B is 60 degrees Find sinA

If angle A is 45 degrees and angle B is 60 degrees.


Find sin(A)cos(B)

½ (sin(105) + sin(345))

½ (sin(105) - sin(345))

½ (sin(345) + cos(105))

½ (sin(345) - cos(105))

Solution

sin(A)cos(B) =(1/2)[sin(A+B)+sin(A-B)]

=(1/2)[sin(45+60)+sin(45-60)]

=(1/2)[sin(105)+sin(-15)]

=(1/2)[sin(105)+sin(345)]

If angle A is 45 degrees and angle B is 60 degrees. Find sin(A)cos(B) ½ (sin(105) + sin(345)) ½ (sin(105) - sin(345)) ½ (sin(345) + cos(105)) ½ (sin(345) - cos(

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