While writing her Ph D dissertation a doctoral student makes
Solution
There is 1 typo every 350 words.
Thus, for a binomial distrbution:
n = 4*250 = 1000 words
p = 1/350 = 0.002857143
x >= 2
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For a Poisson distribution:
There are, on average, 1*(250*4/350) = 2.857142857 typos in 4 pages.
Thus, we want P(x>=2).
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The easier way is the Poisson way, so:
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative poisson distribution table or technology, matching
u = the mean number of successes = 2.857142857
x = our critical value of successes = 2
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 1 ) = 0.221525817
Thus, the probability of at least 2 successes is
P(at least 2 ) = 0.778474183 [ANSWER]
