3 SolutionLet ud u2 u1 Formulating the null and alternativ
Solution
Let ud = u2 - u1.              
 Formulating the null and alternative hypotheses,              
               
 Ho:   ud   =   0  
 Ha:   ud   =/ 0 [ANSWER, OPTION A]
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 At level of significance =    0.1          
 As we can see, this is a    two   tailed test.      
               
 Calculating the standard deviation of the differences (third column):              
               
 s =    2.424621183          
               
 Thus, the standard error of the difference is sD = s/sqrt(n):              
               
 sD =    0.699927846          
               
 Calculating the mean of the differences (third column):              
               
 XD =    1.666666667          
               
 As t = [XD - uD]/sD, where uD = the hypothesized difference =    0   , then      
               
 t =    2.381197827 [test statistic, ANSWER]
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 As df = n - 1 =    11          
               
 Then the critical value of t is              
               
 tcrit =    +/-   1.795884819 [CRITICAL VALUE, ANSWER]
               
 Thus, comparing t and tcrit, we   WE REJECT THE NULL HYPOTHESIS.          
               
 So, YES, AS WE REJECT THE NULL HYPOTHESIS. [ANSWER, OPTION D]
![#3 SolutionLet ud = u2 - u1. Formulating the null and alternative hypotheses, Ho: ud = 0 Ha: ud =/ 0 [ANSWER, OPTION A] ********************** At level of signi #3 SolutionLet ud = u2 - u1. Formulating the null and alternative hypotheses, Ho: ud = 0 Ha: ud =/ 0 [ANSWER, OPTION A] ********************** At level of signi](/WebImages/26/3-solutionlet-ud-u2-u1-formulating-the-null-and-alternativ-1069408-1761559933-0.webp)
