Find a value of x such that 2x ex 1 to the nearest tenthSo

Find a value of x such that 2^x = e^x - 1 to the nearest tenth.

2^x= e^x - 1

e^x - 2^x=1

We have to use guess and check method here

Lets check for x=1

e^1-2^1=.72 approx which is not equal to 1

Lets check for x=1.5

e^1.5 - 2^1.5

1.7 which is greater than 1

It means that the value of x lies between 1 and 1.5

Lets check for x=1.2

e^1.2 - 2^1.2

1 which is equal to right side

Hence x=1.2