Given right triangle ABC with C 90o B 40o and c 20cm so

Given right triangle ABC with C = 90^o , B = 40^o and c = 20cm , solve the triangle

Solution

.A+B+C=180 degrees

A+90+40=180 degrees

A=50 degrees

As we know this is right angled triangle

a=csin50=20 sin50 cm=20*.766cm=15.32cm

b=csin40=20sin40 cm=20*.64cm=12.8cm