A study determined that 9 of children under 18 years old liv

A study determined that 9% of children under 18 years old lived with their father only. Find the probability that none of the children selected at random from 12 children under 18 years old Kved with their father only. The probability that none of the children Kved with their father only is.

Solution

p = 0.09

q = 0.91

Binomial probability distribution: nCr(p)^r(q^(n-r) )

n = 12 ; r =0

Probability of none of the chidren lived with their father only = 12C0(0.09)^0(0.91)^12

= 0.322