Electron is accelerated in the uniform electric field betwee

Electron is accelerated in the uniform electric field between the potential of 100V and 20100V. What is the resulting change of the electron’s kinetic energy ?

Solution

gain in KE = loss in PE

=> 1/2mv^2 = e(V2-V1)

=> 1/2*9.1*10^-31*v^2 = 1.6*10^-19*(20000)\'

change in KE = 3.2*10^-15 J

=> v = 83862786.74 m/s OR 8.38*10^7 m/s

oops i also calculated speed

Electron is accelerated in the uniform electric field between the potential of 100V and 20100V. What is the resulting change of the electron’s kinetic energy ?S

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