Electron is accelerated in the uniform electric field betwee
Electron is accelerated in the uniform electric field between the potential of 100V and 20100V. What is the resulting change of the electron’s kinetic energy ?
Solution
gain in KE = loss in PE
=> 1/2mv^2 = e(V2-V1)
=> 1/2*9.1*10^-31*v^2 = 1.6*10^-19*(20000)\'
change in KE = 3.2*10^-15 J
=> v = 83862786.74 m/s OR 8.38*10^7 m/s
oops i also calculated speed

