Use the halfangle formulas to find the exact value of tan 5p
Use the half-angle formulas to find the exact value of tan 5pi/12
Solution
tan 5pi/12
Use the formula : tan(t/2)=+/-sqrt[(1-cos(t))/(1+cos(t))]
tan(5pi/12) = sqrt [ (1-cos(5pi/6) ) /(1+cos(5pi/6))
cos(5pi/6), we know that cos (pi/6) = 3/2
5pi/6 = pi-pi/6
cos(5pi/6) lies in quadrant II and is negative = -3/2
tan(5pi/12) = sqrt[(1- (-3/2)) / (1 + -3/2)]
= sqrt [(2+3)/(2-3)]
![Use the half-angle formulas to find the exact value of tan 5pi/12Solutiontan 5pi/12 Use the formula : tan(t/2)=+/-sqrt[(1-cos(t))/(1+cos(t))] tan(5pi/12) = sqrt Use the half-angle formulas to find the exact value of tan 5pi/12Solutiontan 5pi/12 Use the formula : tan(t/2)=+/-sqrt[(1-cos(t))/(1+cos(t))] tan(5pi/12) = sqrt](/WebImages/26/use-the-halfangle-formulas-to-find-the-exact-value-of-tan-5p-1070151-1761560447-0.webp)