If a baseball is projected upward from ground level with an

If a baseball is projected upward from ground level with an initial velocity of 32 feet per second, then its height is a function of time, given by s = 16t^2 + 32t. What is the maximum height reached by the ball? The maximum height reached by the ball is feet.

Solution

s = -16t^2 +32t

Its a quadratice function of the form : ax^2 +bx +c =0

Vertex give the maximum value at x= -b/2a

So, for our equation : t = - (32)/( -2*16) = 1

Max. height S occurs at t= 1: s= -16 +32 = 16 feet (Solution)