find the equation of the tangent line and normal line to the
find the equation of the tangent line and normal line to the curve at the given point
y=x^2-x^4
y=x^2-x^4
Solution
differentiating y\' = 2x - 4x^3 point is not given let it be (x0, y0) so equation of tangent = y-y0 = y\'|(x0,y0) [x-x0] and that of normal y-y0 = (-1/y\'|(x0,y0)) [x-x0] where y\'|(x0,y0) means value of y\' at the point (x0, y0)