We randomly selected 5 TV viewers for each of the 3 networks

We randomly selected 5 TV viewers for each of the 3 networks (NBC, ABC, CBS)

We randomly selected 5 TV viewers for each of the 3 networks (NBC, ABC, CBS) A partially complete ANOVA table is provided. Report the missing values that should be in cells (i) to (v). Show your work, rounding values to two decimal places if rounding is necessary. (2.5 pts)

Solution

1) As Total of sum of squares is 100 and

Total sum of squares = Sum of squares of Groups + Sum of squares of error(X)

100 = 80 + X

X =20

2)     Mean Squares = sum squares/ df

40 = 80 / df_g

df_g = 80/40 =2

df_g is degree of freedom of Groups

3)      Total df = df_g + df_e

14 = 2 + df_e

df_e = 12

4) Mean Squares of error = Sum squares of error/ df_e

= 20/ 12                                (from part 1 and 3 solutions)

=1.67

5) F = Mean squares of groups / Mean squares of error

= 40 /1.67

= 24

ANOVA	Sum Squares	df	Mean Squares	F
Groups	80	2	40	24
Error	20	12	1.67
Total	100	14