A typical laboratory electric field is 1400 Vm Find the ave
A typical laboratory electric field is 1400 V/m .
Find the average intensity of an electromagnetic wave with this value for its peak field.
Express your answer to two significant figures and include the appropriate units.
Solution
Iavg = c*Brms^2/uo
Brms = Bmax/sqrt(2)
Iavg = c*Bmax^2/2uo
uo = 4pi * 10^-7
c = speed of light
Bmax = Emax/c = 1400/c
=> I = Emax^2/(c2uo
Iavg = 1400^2)/(2*3*10^8*4*3.14*10^-7) = 2600.84 OR 2.6*10^3 W/m^2
