Trains A and B are travelling in the same direction on paral

Trains A and B are travelling in the same direction on parallel tracks. train A is traveling at 40mph and train b is travelling at44mph. Train A passes a station at 9:10 pm and Train B passes the same station @9:40.
At what time will train b cath up with train?

Solution

Let x = time (in hours) it takes for train B to catch up to train A
Because of the difference in time the two trains passes a station we have:
x + (1/2) = time train A traveled
.
We use the \"distance formula\"
d = rt
where
d is distance traveled
r is rate or speed
t is time
.
For train B to catch up:
\"distance traveled by train A\" = \"distance traveled by train B\"
40(x + (1/2)) = 44x
multiplying both sides by 2:
40(2x + 1) = 88x
80x + 40 = 88x
40 = 8x
5 hours = x
.
But wait, the problem wanted \"clock\" time:
9:40 PM + 5 hours = 2:40 AM