Construct a 90 confidence interval to estimate the populatio

Construct a 90% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample size equal to 125.

Given n=125, p=0.36, q=1-p=1-0.36=0.64. The table value of Z at 10% level of significance is 1.645.

The 90% confidence interval for the population proportion is [p+-(1.645*((pq/n)))]=[0.36+-(1.645*(0.36*0.64/125))]=[0.36+-(1.645*0.0429)]=[0.36+-0.0706]=[0.2894,0.4306].