Colawate the adequeny the o aneng strale al temson a lcu ade
Solution
LRFD DESIGN
The Gross sectional area is Ag=2.86 in2 (from Table 1-7 pg36 of AISC)
For net sectional area,
An= Ag-diameter of hole
An=2.86-3/8(3/8+1/8)
An=2.86-3/8(0.5)
An=2.67in2
assume the 85% of the net effective area
Ae=0.85*2.67=2.26 in2
Gross design yeild strength=xAgxFy=0.9x2.86x36=92.664 Kips
Net section fracture=AeFu=0.75x2.26x58=98.31 Kips
The design strength will be the minimum of the yield strength and fracture
That is 92.664 Kips
The design loads are calculated on the basis of the two equations
1.4D and 1.2D+1.6L
1.4D=1.4x19=26.6 Kips
1.2D+1.6L=1.2(19)+1.6(13)=43.6 Kips
the ultimate load is 43.6 kips which is less than the design strength 92.2 kips, so it is adequate.
ASDThe total load=13+19=32 Kips
ultimate design strength based on yiled and fracture
based on yield=92.664/1.67 (1.67 is the factor of safety)=55.48 kips
based on fracture=98/2=49 kips
so the design strength is more than the allowable load
49 kips>26.6 kips
so it is adequate as per ASD method
