find theta for 0deg

find theta for 0deg <_ theta < 360deg sin theta = -0.8516

sin theta = -0.8516 and 0deg <_ theta < 360deg

theta is sin(theta ) is -ve , so theta is in IIIrd or IVrth quadrant.

theta = sin^-1( -0.8516);

AS theta = sin^-1( 0.8516) = 58.56 deg

theta is in IIIrd or IVrth quadrant.

So, theta = 58.86 + 180 = 238.38 deg

and theta = 360 -58.86 = 301.64 deg