The answer is 49 Could someone please explain that answer Wh

What is the probability that their first child is a female and affected with HD? 34 points) PCHD- 1-P(norma x (2/3) x (1/4)- 1-1/9 8/9 88.9% or you can do: POHD) (113) x (13) x 1+(2/3) x (13) x 2+(2/3) x (2/3) x (3/4) 8/9 88.9% PODaughter and HD): (8/9) x (1/2) 4/9 44.4%

Solution

Answer:

The mentioned probability is wrong

In autosomal dominant inheritance, only one copy of a disease allele is necessary for an individual to be susceptible to expressing the phenotype.

Both parents are affected

Aa x Aa

Children = AA, Aa, Aa, aa

¾ th of children are affected by disease.

Therefore the probability of the child being affected = ¾

The probability of a child being male or female in a birth= ½

Total probability = ¾ x ½ = 3/8