PLEASE ANSWER WILL RATE 3 A mixture of 10 kg of Helium gas M

PLEASE ANSWER WILL RATE

3) A mixture of 10 kg of Helium gas (M=4) and 10 kmols of Hydrogen Gas (M=2) is stored at 100 kPa and 300 K. The volume of the mixture XXX (Enter the nearest three digit integer for XXX)

4) A 100 kg sample of \"Atmospheric Air\" with an absolute humidity ratio 0.016 kg-H2O/kg-DA will contain how many kilograms of H2O vapor? For the 100 kg sample the mass of H2O vapor = X.XXX kg (Enter the answer X.XXX to 3 decimal places)

5) A sample of hot and humid \"Atmospheric Air\" at standard atmospheric pressure (1.01 bar) at the ordinary \"dry bulb\" temperature of 40 deg C has a \"dew point\" temperature of 24 deg C (an oppressive humidity level). Find the relative humidity RH = XX% (Enter a 2 digit integer for relative humidity in %)

6) A 1000 kg-DA sample of hot and humid \"Atmospheric Air\" at standard atmospheric pressure (1.01 bar) at the ordinary \"dry bulb\" temperature of 40 deg C has a \"dew point\" temperature of 24 deg C is cooled to 4 deg C causing a significant amount of condensation to occur. Since condensation is occurring the final state is saturated (100% RH). Find the amount of liquid condensate formed for 1000 kg of dry air, liquid mass = XX kg (Enter your answer rounded to the nearest 2 digit integer)

Solution

3) Volume of Helium gas, V_He= m(R/M)T/P = 10*(8318/4)*300/(100*1000)= 63.385 m³

Volume of Hydrogen gas, V_H = nRT/P = 10 *8318*300/(100*1000)=249.540 m³.

The total volume of the mixture V= 63.385+249.540=312.925 m^3.

4) mass of atmospheric air which contains dry air and moisture(H₂O vapour), m_a= 100 kg

Humidity ratio = mass of H₂O per 1 kg of dry air is = 0.016 kg.

m_w = 0.016 m_d   or m_d = 62.5 m_w.

m_w + m_d = 100 kg

m_w + 62.5 m_w =100

m_w = 100/63.5 = 1.575 kg.

5) Corresponding to DBT of 40⁰C and DPT of 24⁰ C on the psychrometric chart, the relative humidity is 40% approximatey.

6) Liquid condensed mass = 14 kg