54 A For the following assume that all the given angles are
5.4
A)
For the following, assume that all the given angles are in simplest form, so that if A is in QIV you may assume that 270°Solution
sin(A/2)= +-sqrt(1-cosA)/2
Cos A=1/2
therefore sin(A/2)= +-sqrt(1-1/2)/2
sin(A/2)=+- sqrt 1/4
sin(A/2)=+-1/2
And in fourth quadrant sin A is negative,therefore sin(A/2) is negative too
Hence the answer is -1/2
sin A=-4/5
On using pythagoras theorem and trigonometric ratio formula we get
cos A=-3/5
cos(A/2)= +-sqrt(1+cosA)/2
cos(A/2)= +-sqrt(1-3/5)/2
cos(A/2)=+- sqrt 1/5
And in third quadrant cos A is negative,therefore cos (A/2)is negative too
Hence the answer is -sqrt1/5

