thThe genes for miniature wings m and garnet eyes g are appr

thThe genes for miniature wings (m) and garnet eyes (g) are approximately 8 map units apart on chromosome 1 in Drosophila.

Phenotypically wild-type females (m ⁺g / mg ⁺) were mated to miniature-winged males with garnet eyes (mg/mg)

Question : If 800 offspring were produced from the cross, in what numbers would you expect the following phenotypes?

__wild type : __ miniature wings : __ garnet eyes : __ miniature wings, garnet eyes

Please show an explanation with the punnet square.

thank you

Solution

miniature wings..... (m) garnet eyes............ (g) m...............g, separated by approximately 8 mu. wild type (m +g / mg +) x recessive (mg/mg) offspring from the cross........800 recombination frequency between m and g..............8 mu. or 8% Each gene carries.........4 mu or 4% parental + recombinant = 100% 100% - 8% = 92% both the parental crosses gets added to..............92% each parental cross..........46% each wild type cross........ (m +g / mg +) x (mg/mg)............produced 800 wild type = 4% x 800 = 32 miniature wings = 46% x 800 = 368 garnet eyes = 46% x 800 = 368 miniature wings, garnet eyes = 4% x 800 = 32