Feeding the value A to both inputs of a NAND gate yields wha
Solution
5Ans. B. for a NAND gate when A and B are the two inputs then the output is Y = (A.B)\'
Now when feeding the value A to both the inputs of NAND gate then the output is
Y = (A.A)\' = A\' Since acc to AND laws A.A = A
6Ans. B for a NOR gate when A and B are the two inputs then the output is Y = (A+B)\'
Now when feeding the value A to both the inputs of NOR gate then the output is
Y = (A+A)\' = A\' Since acc to OR laws A+A = A
7Ans. C for a NOR gate when A and B are the two inputs then the output is Y = (A+B)\'
Now when feeding the value A to one input and A\' to other input of NOR gate then the output is
Y = (A+A\')\' = 1\' = 0 Since acc to OR laws A+A\' = 1
ie. when A =1 then A + A\' = 1+ 1\'= 1+0 =1
and When A =0 then A+A\' = 0 + 0\' = 0+1 = 1
8Ans. D for a NAND gate when A and B are the two inputs then the output is Y = (A.B)\'
Now when feeding the value A to one input and A\' to other input of NAND gate then the output is
Y = (A.A\')\' = 0\' = 1 Since acc to AND laws A.A\' = 0
ie. when A =1 then A . A\' = 1. 1\'= 1.0 =0
and When A =0 then A.A\' = 0 . 0\' = 0.1 = 0

