An unfair coin comes up heads is 40 Suppose the coin is toss

An unfair coin comes up heads is 40%. Suppose the coin is tossed 15 times. What is the probability that exactly between toss 10 and toss 12 heads occur consecutively?

Solution

We don\'t care what happens from toss 1-9 and toss 13-15.

We just want toss 10 to toss 12 to becomes heads.

Thus, as tosses are independent)

P(toss 10 to toss 12 are heads) = P(3 consecutive heads)

= 0.40^3

= 0.064 [ANSWER]