Factor the polynomial completely Px9x216 PXMy answer and it

Factor the polynomial completely.

P(x)=9x^2+16

P(X)=____________My answer and it is wrong. 9x2+16

Find all its zeros. State the multiplicity of each zero. (If an answer does not exist, enter DNE.)

real zero ____(can\'t find this answer)			with multiplicity	DNE
complex zero	4/3 i	(positive imaginary part)	with multiplicity	2
complex zero	4/3 i	(negative imaginary part)	with multiplicity 2

p(x) = 9x^2 + 16

to factor the polynomial we need two such factors of 9*16 that is 144 that will add up to become 0

there are no such factors that adds up to become zero

hence this polynomial cannot be factored

it is prime polynomial

zeros of the polynomial are

9x^2+16 = 0

9x^2 = -16

x^2 = -16/9

x = + - 4/3 i

therefore , zeros of polynomial are

+ 4/3 i with multiplicity 1

- 4/3 i with multiplicity 1