3 40 points Give examples or explain why no example is possi
Solution
3. (e) Let, xn = (1 + 1/n)n
xn is rational number for all integer n.
Then the sequence {xn} of rational numbers converges to an irrational number e.
Lim (1 + 1/n)n = e as n (This is a standard result)
(f) Let, f(x) = sin (1/x) for all x (0, 1]
Then the function f(x) is continuous, but not uniformly continuous from (0, 1] into R.
Proof:
Let us assume that f is uniformly continuous on (0, 1]. Then for every Cauchy sequence {xn} in (0, 1], the sequence {f(xn)} must be a Cauchy sequence in R. Let us consider the sequence {xn} where xn = 2/(n), n N. This is a Cauchy sequence in (0, 1]. The sequence {f(xn)} is {1, 0, -1, 0, … …}. This is not a Cauchy sequence in R. Therefore, f is not uniformly continuous on (0, 1].
(g) A power series having infinite radius of convergence is xn/n!
Proof:
Let r be the radius of convergence of the power series xn/n!
Then, 1/r = limn |n!/(n+1)!| = limn {1/(n+1)}
Therefore, r = limn (n+1) =
Formula for Radius of convergence r of a power series anxn is given by 1/r = limn |an+1/an|
