In the figure the ideal batteries have emfs 1 100 V and 2

In the figure the ideal batteries have emfs ?₁ = 10.0 V and ?₂ = 0.500 ?₁, and the resistances are each 4.01 ?. What is the value of current in (a) resistor 2 and (b) resistor 3?

Solution

E₁=10v

E₂=o.5 v

r=4.o1ohms

current=

in resisor2

i=v/r =0.5/4.01 =0.124 AMPS

i= v/r =10/4.01 = 2.49 amps