An enzyme aggase requires 16 units of activity for wild type

An enzyme aggase requires >16 units of activity for wild type function. Two alleles of aggase have been identified. Wild type allele A₁ produces 12 units of enzyme and mutant allele A₂ produces 5 units of enzyme.

Which allele is dominant and which is haploinsufficient? Explain your reasoning.

Solution

Wild type allele A1 is dominant and mutant allele A2 is haploinsufficient.This is because a wild type allele produces nearly the same enzyme units i.e 12 units as both the alleles for enzyme aggase must have expressed in it to produce 12 units of the enzyme wheras mutant allele A2 is haploinsufficient as presence of one functional allele (due to muation in other) is not sufficient to produce nearly 16 units of enzyme aggase.