Both 10 and 11 Thanks Determine the limits below by direct s

Both #10 and #11. Thanks!
Determine the limits below by direct substitution, dividing or numerators: lim_x rightarrow 2 x - 2/x^3 - 2x^2 + 2x - 4 =

Solution

10)

x-2)x3-2x2+2x-4(x2+2
......x3-2x2
...............0+2x-4
..................+2x-4
.........................0

limx->2(x-2)/(x3-2x2+2x-4)

=limx->2(x-2)/((x-2)(x2+2))

=limx->2 1/(x2+2)

=1/(22+2)

=1/(4+2)

=1/6

11)limx->0[(x+9) -3]/x

multiply and divide by (x+9) +3

limx->0[((x+9) -3)((x+9) +3)]/[x((x+9) +3)]

limx->0[((x+9)2 -32)]/[x((x+9) +3)]

limx->0[((x+9) -9)]/[x((x+9) +3)]

limx->0[x]/[x((x+9) +3)]

limx->0 1/((x+9) +3)

=1/((0+9) +3)

=1/(3+3)

=1/6

Both #10 and #11. Thanks! Determine the limits below by direct substitution, dividing or numerators: lim_x rightarrow 2 x - 2/x^3 - 2x^2 + 2x - 4 = Solution10)

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