Both 10 and 11 Thanks Determine the limits below by direct s
Both #10 and #11. Thanks!
 Determine the limits below by direct substitution, dividing  or  numerators: lim_x rightarrow 2 x - 2/x^3 - 2x^2 + 2x - 4 =  Solution
10)
x-2)x3-2x2+2x-4(x2+2
 ......x3-2x2
 ...............0+2x-4
 ..................+2x-4
 .........................0
limx->2(x-2)/(x3-2x2+2x-4)
=limx->2(x-2)/((x-2)(x2+2))
=limx->2 1/(x2+2)
=1/(22+2)
=1/(4+2)
=1/6
11)limx->0[(x+9) -3]/x
multiply and divide by (x+9) +3
limx->0[((x+9) -3)((x+9) +3)]/[x((x+9) +3)]
limx->0[((x+9)2 -32)]/[x((x+9) +3)]
limx->0[((x+9) -9)]/[x((x+9) +3)]
limx->0[x]/[x((x+9) +3)]
limx->0 1/((x+9) +3)
=1/((0+9) +3)
=1/(3+3)
=1/6

