Homework SourseAbout of the area under the curve of the standard normal di
About % of the area under the curve of the standard normal distribution is outside the interval z=[0.24,0.24] (or beyond 0.24 standard deviations of the mean).
Solution
Area beyond [-0.24, 0.24] is the probability -
P = P(Z < -0.24) + P(Z > 0.24)
As the Z-distribution is symmetric about Z=0, so we can write -
P = 2 x P(Z < -0.24)
So, P = 2 x 0.4052 = 0.8104.
![About % of the area under the curve of the standard normal distribution is outside the interval z=[0.24,0.24] (or beyond 0.24 standard deviations of the mean).S](/WebImages/27/about-of-the-area-under-the-curve-of-the-standard-normal-di-1071611-1761561410-0.webp "About % of the area under the curve of the standard normal distribution is outside the interval z=[0.24,0.24] (or beyond 0.24 standard deviations of the mean).S")
