5112 Ri 33 k A BJTis connected to the circuit of Fig P599 w

5.112 Ri = 3.3 k A BJTis connected to the circuit of Fig. P5.99 with andul = 10 V. In this case, thei! current source is replaced by a Thévenin circuit consisting of a voltage source V2 = 10 V in series with a resistor of value , (a) Find the values of IB, IC, and UCE If F = 50. (b) Find the values of IB, ic, and UCE if (c) Find a way to eliminate one of the voltage source = 200 powering the circuit.

Solution

Here B indicating current gai Beta

1)

when B=50;

Apply KVL in Base emitter region

V₂=i_BR₂+0.7

i_B=(10-0.7)/1M=9.3uA

i_c=B*i_B=0.465mA

V_CE=V₁-i_cR₁=1.535V

b)B=200

Apply KVL in Base emitter region

V₂=i_BR₂+0.7

i_B=(10-0.7)/1M=9.3uA

i_c=B*i_B=200*9.3uA=1.86mA

V_CE=V₁-i_cR₁=3.862V

c) we can conect the Base terminal with R2 resitance to V1. since V1 and V2 are both are equal.like this way we can eliminate he voltage source v2 or curent source